(3n+2)(n^3-3n+7)=0

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Solution for (3n+2)(n^3-3n+7)=0 equation: 


Simplifying
(3n + 2)(n3 + -3n + 7) = 0

Reorder the terms:
(2 + 3n)(n3 + -3n + 7) = 0

Reorder the terms:
(2 + 3n)(7 + -3n + n3) = 0

Multiply (2 + 3n) * (7 + -3n + n3)
(2(7 + -3n + n3) + 3n * (7 + -3n + n3)) = 0
((7 * 2 + -3n * 2 + n3 * 2) + 3n * (7 + -3n + n3)) = 0
((14 + -6n + 2n3) + 3n * (7 + -3n + n3)) = 0
(14 + -6n + 2n3 + (7 * 3n + -3n * 3n + n3 * 3n)) = 0
(14 + -6n + 2n3 + (21n + -9n2 + 3n4)) = 0

Reorder the terms:
(14 + -6n + 21n + -9n2 + 2n3 + 3n4) = 0

Combine like terms: -6n + 21n = 15n
(14 + 15n + -9n2 + 2n3 + 3n4) = 0

Solving
14 + 15n + -9n2 + 2n3 + 3n4 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.

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